execute Thread.interrupt() Object.notify() at the same time, why does has two results?

Question

public class WaitNotifyAll {
    private static volatile Object resourceA = new Object();

    public static void main(String[] args) throws Exception {
        Thread threadA = new Thread(new Runnable() {
            @Override
            public void run() {
                synchronized (resourceA) {
                    try {
                        System.out.println("threadA begin wait");
                        resourceA.wait();
                        System.out.println("threadA end wait");
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                }
            }
        });

        Thread threaB = new Thread(new Runnable() {
            @Override
            public void run() {
                synchronized (resourceA) {
                    System.out.println("threadC begin notify");
                    threadA.interrupt();
                    resourceA.notify();
                }
            }
        });

        threadA.start();

        Thread.sleep(1000);

        threaB.start();

        System.out.println("main over");
    }
 }

There are two possible result here：

1. throws InterruptedException

2. normal termination

why?

I don't understand. when threadA is interruptted ,result should throws InterruptedException. but sometimes execute this program, it can normal finish.

environment： java8， mac

Answer 1

When a thread receives both an interrupt and a notify, the behaviour may vary.

Please refer to https://docs.oracle.com/javase/specs/jls/se7/html/jls-17.html#jls-17.2.3

Credit - Alex Otenko on the Concurrency Interest mailing list