C++: Using remove_if to filter vector on a condition

What is the correct syntax to use erase+remove_if to remove all elements in a vector, that are smaller than a specific value. However, this specific value is not a constant, but a variable.

Refer to the code to get a better understanding of the question:

for (int i = 0; i < arr.size(); i++)
{
    int currEle = arr[i];

    /*
        How do I use erase + remove_if to remove the elements from arr that
        are smaller than currEle? 
    */

}

Solution

Below example demonstrates the usage of erase-remove_if. limit is captured by reference and can thus be modified outside the lambda:

#include <vector>
#include <algorithm>
#include <iostream>
int main()
{
    std::vector<int> vec{0,1,2,3,4,5,6,7,8,9};
    int size = vec.size();
    for (int limit = 0; limit <= size; limit++)
    {
        vec.erase(std::remove_if(std::begin(vec), std::end(vec), [&limit](int i) {
            return i < limit;
        }), std::end(vec));
        for (auto& v : vec)
            std::cout << v;
        std::cout << std::endl;
    }
    return 0;
}

Expected output: