I have a dictionary with objects as values. These objects are instances of the following class:
Class A():
def __init__(self, x=''):
self.x = x
self.count = 0
The dictionary entries will therefore be of the form: {'some_key', instance_of_class_A}
Now, I would like to sort the dictionary on the the value of A.count within the instance_of_A.
I have failed to find an answer to this through numerous searches so am hoping someone has solved this before! Thanks P.
To sort the values of a dictionary, you can do the following:
sorted_values = sorted(dict.values(), key=lambda x: x.count)
I do not see the need for sorting an entire dictionary, however. If the key value can hold a list of A
objects and you want to sort that:
dict[key] = sorted(dict[key], key=lambda x: x.count)