In NodeJS, I can declare a callback in one place and use it in one place to avoid breaking the structure of the project.
A.js
module.exports = class A(){
constructor(name, callback){
this.name = name;
this.callback = callback;
}
doSomeThingWithName(name){
this.name = name;
if(this.callback){
this.callback();
}
}
}
B.js
const A = require(./A);
newA = new A("KimKim", ()=> console.log("Say Oyeah!"));
In Go, I also want to do the same thing like this with interface and implement.
A.go
type canDoSomething interface {
DoSomething()
}
type AStruct struct {
name string
callback canDoSomething
}
func (a *AStruct) DoSomeThingWithName(name string){
a.name = name;
a.callback.DoSomething()
}
B.go
import (A);
newA = A{}
newA.DoSomeThingWithName("KimKim");
Can I overwrite logic for interface functions in file B.go? How could I do to make them equivalent to NodeJS's style?
I try
import (A);
newA = A{}
// I want
//newA.callback.DoSomething = func(){}...
// or
// func (a *AStruct) DoSomething(){}...
// :/
newA.DoSomeThingWithName("KimKim");
Functions are first class values in Go, just like they are in JavaScript. You don't need an interface here (unless there is some other goal that you are not stating):
type A struct {
name string
callback func()
}
func (a *A) DoSomeThingWithName(name string){
a.name = name;
a.callback()
}
func main() {
a := &A{
callback: func() { /* ... */ },
}
a.DoSomeThingWithName("KimKim")
}
Since all types can have methods, all types (including function types) can implement interfaces. So if you really want to you can let A depend on an interface and define a function type for providing implementations on-the-fly:
type Doer interface {
Do()
}
// DoerFunc is a function type that turns any func() into a Doer.
type DoerFunc func()
// Do implements Doer
func (f DoerFunc) Do() { f() }
type A struct {
name string
callback Doer
}
func (a *A) DoSomeThingWithName(name string) {
a.name = name
a.callback.Do()
}
func main() {
a := &A{
callback: DoerFunc(func() { /* ... */ }),
}
a.DoSomeThingWithName("KimKim")
}