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node.jsgointerfacecallbackimplements

Implementing interface from different package (callback from other module)


In NodeJS, I can declare a callback in one place and use it in one place to avoid breaking the structure of the project.

A.js

module.exports = class A(){
    constructor(name, callback){
        this.name = name;
        this.callback = callback;
    }
    doSomeThingWithName(name){
        this.name = name;
        if(this.callback){
            this.callback();
        }
    }
}

B.js

const A = require(./A);
newA = new A("KimKim", ()=> console.log("Say Oyeah!"));

In Go, I also want to do the same thing like this with interface and implement.

A.go

type canDoSomething interface {
    DoSomething()
}
type AStruct struct {
    name string
    callback canDoSomething
}
func (a *AStruct) DoSomeThingWithName(name string){
    a.name = name;
    a.callback.DoSomething()
}

B.go

import (A);
newA = A{}
newA.DoSomeThingWithName("KimKim");

Can I overwrite logic for interface functions in file B.go? How could I do to make them equivalent to NodeJS's style?

I try

import (A);
newA = A{}

// I want
//newA.callback.DoSomething = func(){}...
// or
// func (a *AStruct) DoSomething(){}...
// :/
newA.DoSomeThingWithName("KimKim");

Solution

  • Functions are first class values in Go, just like they are in JavaScript. You don't need an interface here (unless there is some other goal that you are not stating):

    type A struct {
        name string
        callback func()
    }
    
    func (a *A) DoSomeThingWithName(name string){
        a.name = name;
        a.callback()
    }
    
    func main() {
        a := &A{
            callback: func() { /* ... */ },
        }
    
        a.DoSomeThingWithName("KimKim")
    }
    

    Since all types can have methods, all types (including function types) can implement interfaces. So if you really want to you can let A depend on an interface and define a function type for providing implementations on-the-fly:

    type Doer interface {
        Do()
    }
    
    // DoerFunc is a function type that turns any func() into a Doer.
    type DoerFunc func()
    
    // Do implements Doer
    func (f DoerFunc) Do() { f() }
    
    type A struct {
        name     string
        callback Doer
    }
    
    func (a *A) DoSomeThingWithName(name string) {
        a.name = name
        a.callback.Do()
    }
    
    func main() {
        a := &A{
            callback: DoerFunc(func() { /* ... */ }),
        }
    
        a.DoSomeThingWithName("KimKim")
    }