I've got digest value of data in string format, and I'd like to hexify it.
Here's the sample string '\xf0z\xd8[\xfc\x7f'
However, I cannot use hashlib since I don't have the original data from which the hash was created from.
trying .digesthex() on the string wouldn't work since str object don't have that method. Is there any alternative ?
For each character in the original string, use ord to obtain the numeric value of the character and then use a string format operation to express that numeric value as a string containing a pair of hex digit characters. Accumulate those two-digit strings into a single string.
mystring = '\xf0z\xd8[\xfc\x7f'
result = ''
for ch in mystring:
number = ord(ch)
hexdigits = '{:02x}'.format(number)
result += hexdigits
print result
You can do all of that on one line by using a list comprehension to collect the pairs of hex digit strings into a list and then using the join method with an empty separator string to glue the hex digit strings together into a single string.
mystring = '\xf0z\xd8[\xfc\x7f'
result = ''.join([ '{:02x}'.format(ord(ch)) for ch in mystring ])
print result
Or instead of a list comprehension you can use map with a lambda to build the list of hex digit pairs.
mystring = '\xf0z\xd8[\xfc\x7f'
result = ''.join(map(lambda ch: '{:02x}'.format(ord(ch)), mystring))
print result
The map version is harder to read but it might run slightly faster.