how to recast and print variables in lldb

I have a pointer to a string

void *s = "now is the time for all"

and I wish to print it as an integer of 32-bit size:

gdb) p /x *((int *)s)

What is the equivalence in lldb parlance?

Solution

Exactly that, except you can't put a space between the p and the /x.

lldb's command syntax is not the same as lldb's (for more details see:

http://lldb.llvm.org/tutorial.html

) but p (among others) was added (as an alias to the lldb expr command) for people more familiar with gdb's commands. However, to get the /x part working through lldb's command parser it has to be directly postpended to the actual command name so it isn't confused with arguments and options. So:

(lldb) p/x *((int *) text_to_use)
(int) $1 = 0x8f06c8c0

There's also a cheat sheet for lldb <-> gdb commands here:

http://lldb.llvm.org/lldb-gdb.html

which you might find handy.