How to copy values for the char **a - C

Question

In this code:

#include <stdio.h>
void givetome(char** skey);
int main(int argc, const char * argv[]) {
    char *skey[5];
    givetome(&skey[5]);
    printf("%s\n",*skey);
    return 0;
}
void givetome(char **skey){
    char f[5]={'g','h','f','d','s'};
    for (int i=0; i<5; i++) {
        *skey[i]=f[i];
    }
}

I'm not able to copy the values from the vector "f" to the vector "skey". Someone to help?

Answer 1

With givetome(&skey[5]), you start assigning characters at the end of skey and thereby exceed array bounds then. With givetome(&skey[0]) or simply givetome(skey) it should work.

BTW: as you print the result as a string, you'll need to terminate the string with '\0':

#include <stdio.h>
void givetome(char* skey);
int main(int argc, const char * argv[]) {
    char skey[6];
    givetome(skey);
    skey[5] = '\0';
    printf("%s\n",skey);
    return 0;
}
void givetome(char *skey){
    char f[5]={'g','h','f','d','s'};
    for (int i=0; i<5; i++) {
        skey[i]=f[i];
    }
}