I am trying to read the data of large excel file(almost 100000 row). I am using 'xlrd Module' in python to fetch the data from excel. I want to fetch data by column name(Cascade,Schedule Name,Market) instead of column number(0,1,2). Because my excel columns are not fixed. i know how to fetch data in case of fixed column.
here is the code by which i am fetching data from the excel for fixed column
import xlrd
file_location =r"C:\Users\Desktop\Vision.xlsx"
workbook=xlrd.open_workbook(file_location)
sheet= workbook.sheet_by_index(0)
print(sheet.ncols,sheet.nrows,sheet.name,sheet.number)
for i in range(sheet.nrows):
flag = 0
for j in range(sheet.ncols):
value=sheet.cell(i,j).value
If anyone has any solution of this, kindly let me know
Thanks
Comment: still not working when header of
fieldnames = ['Cascade', 'Market', 'Schedule', 'Name]
and
Sheet(['Cascade', 'Schedule', 'Name', 'Market'])
are equal.
Keep order of fieldnames
in col_idx
, was not my initial goal.
Question: I want to fetch data by column name
The following OOP
solution will work:
class OrderedByName():
"""
Privides a generator method, to iterate in Column Name ordered sequence
Provides subscription, to get columns index by name. using class[name]
"""
def __init__(self, sheet, fieldnames, row=0):
"""
Create a OrderedDict {name:index} from 'fieldnames'
:param sheet: The Worksheet to use
:param fieldnames: Ordered List of Column Names
:param row: Default Row Index for the Header Row
"""
from collections import OrderedDict
self.columns = OrderedDict().fromkeys(fieldnames, None)
for n in range(sheet.ncols):
self.columns[sheet.cell(row, n).value] = n
@property
def ncols(self):
"""
Generator, equal usage as range(xlrd.ncols),
to iterate columns in ordered sequence
:return: yield Column index
"""
for idx in self.columns.values():
yield idx
def __getitem__(self, item):
"""
Make class object subscriptable
:param item: Column Name
:return: Columns index
"""
return self.columns[item]
Usage:
# Worksheet Data
sheet([['Schedule', 'Cascade', 'Market'],
['SF05UB0', 'DO Macro Upgrade', 'Upper Cnetral Valley'],
['DE03HO0', 'DO Macro Upgrade', 'Toledo'],
['SF73XC4', 'DO Macro Upgrade', 'SF Bay']]
)
# Instantiate with Ordered List of Column Names
# NOTE the different Order of Column Names
by_name = OrderedByName(sheet, ['Cascade', 'Market', 'Schedule'])
# Iterate all Rows and all Columns Ordered as instantiated
for row in range(sheet.nrows):
for col in by_name.ncols:
value = sheet.cell(row, col).value
print("cell({}).value == {}".format((row,col), value))
Output:
cell((0, 1)).value == Cascade cell((0, 2)).value == Market cell((0, 0)).value == Schedule cell((1, 1)).value == DO Macro Upgrade cell((1, 2)).value == Upper Cnetral Valley cell((1, 0)).value == SF05UB0 cell((2, 1)).value == DO Macro Upgrade cell((2, 2)).value == Toledo cell((2, 0)).value == DE03HO0 cell((3, 1)).value == DO Macro Upgrade cell((3, 2)).value == SF Bay cell((3, 0)).value == SF73XC4
Get Index of one Column by Name
print("cell{}.value == {}".format((1, by_name['Schedule']), sheet.cell(1, by_name['Schedule']).value)) #>>> cell(1, 0).value == SF05UB0
Tested with Python: 3.5