Write a SQL query to get the second highest salary from the Employee table.
| Id | Salary |
| 1 | 100 |
| 2 | 200 |
| 3 | 300 |
For example, given the above Employee table, the query should return 200 as the second highest salary. If there is no second highest salary, then the query should return null.
| SecondHighestSalary |
| 200 |
This is a question from Leetcode, for which I entered the following code:
SELECT CASE WHEN Salary = ''
THEN NULL
ELSE Salary
END AS SecondHighestSalary
FROM (SELECT TOP 2 Salary
,ROW_NUMBER() OVER (ORDER BY Salary DESC) AS Num
FROM Employee
ORDER BY Salary DESC) AS T
WHERE T.Num = 2
It says that the query does not return NULL if there's no value for second highest salary. For eg. if the table is
| Id | Salary|
| 1 | 100 |
The query should return
|SecondHighestSalary|
| null |
and not
|SecondHighestSalary|
| |
In case of ties you want the second highest distinct value. E.g. for values 100, 200, 300, 300, you want 200.
So get the highest value (MAX(salary)
=> 300) and then get the highest value less than that:
select max(salary) from mytable where salary < (select max(salary) from mytable);