I'm trying to create a very simple ApplicationWindow using PySide2 (Qt for Windows) and QML.
main.py
import sys
from PySide2.QtWidgets import QApplication
from PySide2.QtCore import QUrl
from PySide2.QtQml import QQmlApplicationEngine
if __name__ == "__main__":
app = QApplication(sys.argv)
url = QUrl("mainWindow.qml")
engine = QQmlApplicationEngine()
engine.load(url)
sys.exit(app.exec_())
qml file
import QtQuick.Controls 2.4
ApplicationWindow {
id: mainWindow
visible: true
title: "MainWindow"
width: 640
height: 480
menuBar: MenuBar {
id: menuBar
Menu {
id: editMenu
title: "&Edit"
MenuItem {
id: copyItem
text: "Copy"
// This doesn't work:
// shortcut: "Ctrl+C"
// This doesn't work either:
// shortcut: StandardKey.Copy
}
}
}
}
As shown, the code runs and displays an ApplicationWindow with a MenuBar and the Menu. But if I outcomment either of the two shortcut variants the window isn't shown at all. I don't understand, why. My example follows the Qt documentation on MenuItems.
In QML there are 2 types of items: Qt Quick Controls 1
and Qt Quick Controls 2
. Both groups have items with the same name but they differ in their properties, in your case MenuItem
of Qt Quick Controls 2
does not have a shortcut property but instead Qt Quick Controls 1
if it has it so the solution is to change the import:
import QtQuick 2.11 // <---
import QtQuick.Controls 1.4 // <---
ApplicationWindow {
id: mainWindow
visible: true
title: "MainWindow"
width: 640
height: 480
menuBar: MenuBar {
id: menuBar
Menu {
id: editMenu
title: "&Edit"
MenuItem {
id: copyItem
text: "Copy"
shortcut: StandardKey.Copy
onTriggered: console.log("copy")
}
}
}
}