I have this code:
L = [1, x, x**2]
L2 = [1, 2*x]
def my_mul(x,y):
if x == None: return y
if y == None: return x
return x*y
map(my_mul, L, L2)
This produces what I want, which is a element-wise product of L and L2.
[1, 2*x^2, x^2]
But is there a more pythonic way of achieving this?
Concretely, can I do this without defining my own function?
The code below should achieve what you need
import itertools
import operator
l1 = [1, 2, 3]
l2 = [1, 2, 3, 4]
list(itertools.starmap(operator.mul, itertools.zip_longest(l1, l2, fillvalue=1)))
# result [1, 3, 9, 4]
zip_longest
will zip and fill missing values from shorter list:
itertools.zip_longest(l1, l2, fillvalue=1)
[(1, 1), (2, 2), (3, 3), (1, 4)]
starmap
will apply multiplication operator to every integer pair