LocalTime() difference between two times

Question

I have a flight itinerary program where I need to get difference between departure and arrival time. I get these specified times as String from the data. Here is my problem:

import static java.time.temporal.ChronoUnit.MINUTES;
import java.time.LocalTime;
import java.time.format.DateTimeFormatter;

public class test2 {
public static void main(String[] args) {

    DateTimeFormatter dateFormat = DateTimeFormatter.ofPattern("HHmm");
    LocalTime departure = LocalTime.parse("1139", dateFormat);
    LocalTime arrival = LocalTime.parse("1435", dateFormat);
    LocalTime a = LocalTime.parse("0906", dateFormat);
    System.out.println(MINUTES.between(departure, arrival));
    System.out.println(MINUTES.between(arrival, a));
}
}

Output:

176
-329

The first time returns the difference between 11:39 and 14:35 just fine. But the second difference is only 5 hours while it should be 19 hours. How can I fix this, what am I doing wrong here?

Any help would be greatly appreciated.

EDIT: I am using graphs to store my data in. An example of a shortest route between two airports is like this:

Route for Edinburgh to Sydney
1 Edinburgh, 1139, TK3245, Istanbul, 1435
2 Istanbul, 0906, TK4557, Singapore, 1937
3 Singapore, 0804, QF1721, Sydney, 1521

These are the 3 flights that takes us from EDI to SYD. The format of the output above is (City, Departure Time, Flight No., Destination, Arrival Time).

Answer 1

The total number of minutes in 24 hours is 1440. So when the difference is below zero (but you need a positive one) then you should add a whole day to your result:

int diff = MINUTES.between(arrival, a);
if (diff < 0) {
    diff += 1440;
}

You can achieve the same thing using this:

int diff = (MINUTES.between(arrival, a) + 1440) % 1440;