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rpipeprogramming-languagesdata-sciencemagrittr

How can I write this R expression in the pipe operator format?

I am trying to rewrite this expression to magrittr’s pipe operator:

print(mean(pull(df, height), na.rm=TRUE))

which returns 175.4 for my dataset.

I know that I have to start with the data frame and write it as >df%>% but I’m confused about how to write it inside out. For example, should the na.rm=TRUE go inside mean(), pull() or print()?

UPDATE: I actually figured it out by trial and error...

>df%>%
+pull(height)%>%
+mean(na.rm=TRUE)
+print()

returns 175.4
Solution

  • It would be good practice to make a reproducible example, with dummy data like this:

    height <- seq(1:30)
weight <- seq(1:30)
df <- data.frame(height, weight)

    These pipe operators work with the majority of the tidyverse (not just magrittr). What you are trying to do is actually coming out of dplyr. The na.rm=T is required for many summary variables like mean, sd, as well as certain functions used to gather specific data points like min, max, etc. These functions don't play well with NA values.

    df %>% pull(height) %>% mean(na.rm=T) %>% print()

    Unless your data is nested you may not even need to use pull

    df %>% summarise(mean = mean(height,na.rm=T))

    Also, using summarise you can pipe these into another dataframe rather than just printing, and call them out of the dataframe whenever you want.

    df %>% summarise(meanHt = mean(height,na.rm=T), sdHt = sd(height,na.rm=T)) -> summary
summary[1]
summary[2]