Check if number has its digits in order

Question

I am trying to check if, given any number, its digits are in order. Example:

1479 -> TRUE

1293 -> FALSE

Is there a proper way to do this in Haskell? I am new to the language and feel really lost at the moment. Thank you.

Answer 1

My idea is this:

ordenado n
   | mod n 10 > mod (div n 10) 10 = ordenado (div n 10)
   | n == 0 = True
   | otherwise = False