I have the following table in SQL Server;
DesiredRowNo. Customer Date NID SID Contacts AG
1 AAA 04/09/2018 15357989260016600 100743 1 1
1 AAA 04/09/2018 15358110980018300 100743 1 1
1 AAA 04/09/2018 15358197620012800 100743 1 1
2 AAA 21/09/2018 15358902310016400 100743 1 1
2 AAA 21/09/2018 15358999300015200 100743 1 1
3 AAA 29/09/2018 15359624190012200 100743 1 1
3 AAA 29/09/2018 15359896100010500 100702 1 1
4 AAA 30/09/2018 15360551640011900 100743 1 1
1 BBB 05/09/2018 15357989260016600 100743 1 1
1 BBB 05/09/2018 15358110980018300 100743 1 1
2 BBB 08/09/2018 15358197620012800 100743 1 1
3 BBB 15/09/2018 15358902310016400 100743 1 1
3 BBB 15/09/2018 15358999300015200 100743 1 1
4 BBB 19/09/2018 15359624190012200 100743 1 1
5 BBB 24/09/2018 15359896100010500 100702 1 1
5 BBB 24/09/2018 15360551640011900 100743 1 1
I need the 1st column (DesiredRowNo.) to display a rank/row number based on the customer and the date. So for Customer AAA, all the rows with same date ranked as 1, then the next unique date ranked as 2, and so on. (has to be sequential based on date)
See the DesiredRowNo. values above for a better explanation as to what I'm trying to achieve.
Ive tried using;
ROW_NUMER() over (partition by Customer, date order by date)
But this doesnt seem to give the correct sequencing as required.
Any ideas?
Ooops, this was a massive oversight. Ive fixed it using this:
DENSE_RANK() over (partition by Customer order by date)
Thanks for your steer Larnu