I want to get the address from the coordinate. I have attached my code below..
func locationManager(_ manager: CLLocationManager, didUpdateLocations locations: [CLLocation]) {
let lastLocation = locations.last!
let latvalue = lastLocation.coordinate.latitude
let lngvalue = lastLocation.coordinate.longitude
self.db_latvalue = latvalue
self.db_lngvalue = lngvalue
let location = CLLocation(latitude: latvalue, longitude:lngvalue)
let address = CLGeocoder.init()
address.reverseGeocodeLocation(CLLocation.init(latitude: latvalue, longitude:lngvalue)) { (places, error) in
if error == nil{
if let place = places{
print("addressshowingssq \(place)")
self.db_address = "\(place)"
}
}
}
Output:
[L-30 2nd A Main Road, L-30 2nd A Main Road, HSR Layout, Bengaluru, Karnataka 560102, India @ <+12.91597974,+77.62879254> +/- 100.00m, region CLCircularRegion (identifier:'<+12.91597974,+77.62879254> radius 70.94', center:<+12.91597974,+77.62879254>, radius:70.94m)]
I want only the address as i mention below
L-30 2nd A Main Road, L-30 2nd A Main Road, HSR Layout, Bengaluru, Karnataka 560102
I researched google i got different solution so i got confused.
I have done a few modification to iVarun's
solution. This is simpler. and working.
First, add this function:
func geocode(latitude: Double, longitude: Double, completion: @escaping (CLPlacemark?, Error?) -> ()) {
CLGeocoder().reverseGeocodeLocation(CLLocation(latitude: latitude, longitude: longitude)) { completion($0?.first, $1) }
}
After that, get the address:
geocode(latitude: latvalue, longitude: lngvalue) { placemark, error in
guard let placemark = placemark, error == nil else { return }
// you should always update your UI in the main thread
DispatchQueue.main.async {
// update UI here
print("address1:", placemark.thoroughfare ?? "")
print("address2:", placemark.subThoroughfare ?? "")
print("city:", placemark.locality ?? "")
print("state:", placemark.administrativeArea ?? "")
print("zip code:", placemark.postalCode ?? "")
print("country:", placemark.country ?? "")
}
}
Result:
address1: Rua Casuarina
address2: 443
city: Rio de Janeiro
state: RJ
zip code: 20975
country: Brazil
As @iOSer indicated, CLPlacemark
is capable of giving you this part of the string, However.
You could split the string:
let output:String = "[L-30 2nd A Main Road, L-30 2nd A Main Road, HSR Layout, Bengaluru, Karnataka 560102, India @ <+12.91597974,+77.62879254> +/- 100.00m, region CLCircularRegion (identifier:'<+12.91597974,+77.62879254> radius 70.94', center:<+12.91597974,+77.62879254>, radius:70.94m)]"
let items = output.components(separatedBy: "@")
print(items[0])
Becuse the @
will be always included, you could skip the rest.