Trying to run my program through java web start. I get the following exception in the output console. Im new to java web start so do any of you have any ideas?
FYI, here is line 66
ConfigFileReader cfg = new ConfigFileReader(BCApp.getConfigFileLocation());
java.lang.reflect.InvocationTargetException
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
at com.sun.javaws.Launcher.executeApplication(Unknown Source)
at com.sun.javaws.Launcher.executeMainClass(Unknown Source)
at com.sun.javaws.Launcher.doLaunchApp(Unknown Source)
at com.sun.javaws.Launcher.run(Unknown Source)
at java.lang.Thread.run(Unknown Source)
Caused by: java.lang.ExceptionInInitializerError
at JCS.Main$setStyle.setStyle(Main.java:66)
at JCS.Main.main(Main.java:57)
... 9 more
Caused by: java.security.AccessControlException: access denied (java.util.PropertyPermission java.io.tmpdir read)
at java.security.AccessControlContext.checkPermission(Unknown Source)
at java.security.AccessController.checkPermission(Unknown Source)
at java.lang.SecurityManager.checkPermission(Unknown Source)
at java.lang.SecurityManager.checkPropertyAccess(Unknown Source)
at java.lang.System.getProperty(Unknown Source)
at GUI.BCApp.(BCApp.java:60)
... 11 more
You are going to want to read up on the security manager. Because code launched through Java Web Start could potentially cause grave harm to client computers there are a lot of things it is usually not allowed to do. File system access is one of them. There are several ways to enable your Java Web Start app to access the file system detailed in the documentation.