C# How do i resume the execution of my code after a catch?

Question

Is it possible to resume the execution of my Programm after the first catch even if i throwed the exception?

I made an example programm but the line where i added the exception to my List<string> has to be executed exactly after the inner and inside the outer foreach i know it would be possible if i wouldnt throw the exception but i have to do this aswell.

foreach(var x in x)
{
    try
    {
        List<string> exs = new List<string>();
        foreach(var a in b)
        {
            try
            {
                //...some code
            }
            catch(Exception ex)
            {
                throw ex;
            }
            finally
            {
                //...some code
            }
        }
        exs.Add(ex);
    }
    catch(Exception ex)
    {
        Console.WriteLine(ex);
    }
    finally
    {
        //...some code
    }
}

Answer 1

Don't throw them, but collect and print them later.

List<Exception> exs = new List<Exception>();
try
{

    foreach(var a in b)
    {
        try
        {
            //...some code
        }
        catch(Exception ex)
        {
            exs.Add(ex);
        }
        finally
        {
            //...some code
        }
    }        
}    
catch(Exception e)
{
   Console.WriteLine(e.ToString());
}
finally
{
    //...some code
}
exs.ForEach(ex=> Console.WriteLine(ex.ToString()));