Accessing a tuple in enumerate?

Question

I want to iterate through a list and sum all the elements. Except, if the number is a 5, I want to skip the number following that 5. So for example:

x=[1,2,3,4,5,6,7,5,4,3] #should results in 30.

I'm just not sure how I can access the index of a tuple, when I use enumerate. What I want to do, is use an if statement, that if the number at the previous index == 5, continue the loop.

Thanks you

Answer 1

Not a fan of bug-ridden one-liners that get upvoted.

So here's the answer with a for-loop.

x=[1,2,3,4,5,6,7,5,4,3, 5] #should results in 35. 

s = 0
for i, v in enumerate(x):
    if i != 0 and x[i-1] == 5: 
        continue 
    s += v

print(s)