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c++performanceinitializationbuilt-in-types

0 initialization of C++ built-in types

suppose I have this struct (or class, my question applies to both):

struct builtin 
{ 
    int a;
    int b; 
    builtin() : a(), b(0) { } 
};

I know that both a and b will be initialized to 0 by the constructor of builtin. My question is: Is one method faster than the other?

Solution

  • Answer: no. The compiled code is identical.