I am programming in Z80 assembly; I'm confused about endianness.
Regarding the following instruction:
LD HL,d16
Will the bytes 21 FF DF
result in H = FF
and L = DF
or H = DF
and L = FF
?
Z80 datasheet, p.54 (page #74 in the PDF):
In all extended immediate or extended addressing modes, the low order byte always appears first after the Op Code.
So when the instruction opcode is 21 FF DF
, LSB = FF.