Python schedule :missing 1 required positional argument?

Question

This is my code.

from API.helpers import get_weather_data, json_to_df, create_dict
import schedule, time

URL = 'https://pm1aapplicantsdata.blob.core.windows.net/databases/CitiesWeather/CitiesWeather.csv'
columns = ["name","sys.country","main.temp",
           "main.humidity","main.pressure",
           "visibility", "wind.speed"]

def weather_api(URL):
    dict = create_dict(URL)
    for city, code in dict.items():
        data = get_weather_data(city, code)
        json_to_df(data, columns)

schedule.every(10).minutes.do(weather_api())
while True:
    schedule.run_pending()
    time.sleep(1)

What I want to do is to run it on some regular intervals. However, I am getting an error saying "weather_api() missing 1 required positional argument: 'URL'". I've tried to pass it into the schedule schedule.every(10).minutes.do(weather_api(URL)) but then I am getting the first argument must be callable error. Also in this case...

def weather_api():
    URL = 'https://pm1aapplicantsdata.blob.core.windows.net/databases/CitiesWeather/CitiesWeather.csv'
    dict = create_dict(URL)
    for city, code in dict.items():
        data = get_weather_data(city, code)
        json_to_df(data, columns)

schedule.every(10).minutes.do(weather_api())
while True:
    schedule.run_pending()
    time.sleep(1)

...the error remains. I have tried to use Advanced Python Scheduler before but the problem was same. My script works fine otherwise. What am I doing wrong?

Answer 1

See the source code of schedule

You may want to use schedule.every(10).minutes.do(weather_api, URL)