If statement get's a skipped, while only else statement get's printed .And how do I store a string or int in a single variable?

Question

I was trying to do an exercise ,which asked us to solve this following problem Exercise problem image which I tried to do ,but by not using same exact keywords as shown in the exercise.

Here is my code

def StringLength(length_of_String):
    return len(text)

text = input("length_of_String :")

if type(text) == int:
    print ("python doesn't show length of integers")
else :
    print (len(text))

But the problem I get here is , if I add any text say like"joker" . It will output me length as "5",which is correct .

But when I type any integer or float , say "101" , it still prints it length as "3" because it is reading it as a string.

So how come I add Variable in which when I input a integer or string , it should recognise it as a string or an integer

Answer 1

some_variable = input() by default will give you string. You may want to modify your code:

def is_number(s):
try:
    float(s)
    return True
except ValueError:
    return False

def StringLength():
    text = input('Enter:')
    if is_number(text):
        print ("python doesn't show length of integers")
    else :
        return(len(text))

#StringLength() #Remove the '#' at the start of the line to test the function

Edit: I have added a function to test if the entered value is a number or not