I'm using reticulate R package and want to configure python3 with it, however not able to do it. I tried the following code
library(reticulate)
packageVersion("reticulate")
# [1] ‘1.10.0.9002’
use_python(python = "/usr/bin/python", required = TRUE)
py_config()
# python: /usr/bin/python
# libpython: /usr/lib/python2.7/config-x86_64-linux-gnu/libpython2.7.so
# pythonhome: /usr:/usr
# version: 2.7.15rc1 (default, Apr 15 2018, 21:51:34) [GCC 7.3.0]
# numpy: /usr/lib/python2.7/dist-packages/numpy
# numpy_version: 1.13.3
#
# NOTE: Python version was forced by use_python function
Sys.which("python3")
# python3
# "/usr/bin/python3"
use_python(python = "/usr/bin/python3", required = TRUE)
py_config()
# python: /usr/bin/python
# libpython: /usr/lib/python2.7/config-x86_64-linux-gnu/libpython2.7.so
# pythonhome: /usr:/usr
# version: 2.7.15rc1 (default, Apr 15 2018, 21:51:34) [GCC 7.3.0]
# numpy: /usr/lib/python2.7/dist-packages/numpy
# numpy_version: 1.13.3
#
# NOTE: Python version was forced by use_python function
Any hints, please.
Do not run
use_python(python = "/usr/bin/python", required = TRUE)
before configuring into python3. As discussed here, only one python interpreter is allowed for an R session.
Here is what I saw on my laptop if use_python is only configured for python3:
library(reticulate)
use_python(python = Sys.which("python3"), required = TRUE)
py_config()
# python: /usr/local/bin/python3
# libpython: /usr/local/Cellar/python3/3.5.2_1/Frameworks/Python.framework/Versions/3.5/lib/python3.5/config-3.5m/libpython3.5.dylib
# pythonhome: /usr/local/Cellar/python3/3.5.2_1/Frameworks/Python.framework/Versions/3.5:/usr/local/Cellar/python3/3.5.2_1/Frameworks/Python.framework/Versions/3.5
# version: 3.5.2 (default, Jul 28 2016, 21:28:00) [GCC 4.2.1 Compatible Apple LLVM 7.3.0 (clang-703.0.31)]
# numpy: /usr/local/lib/python3.5/site-packages/numpy
# numpy_version: 1.12.0
#
# NOTE: Python version was forced by use_python function