Python: run bash commands sequentially

Question

I am running an executable on a bunch of *.in files in a directory. My script dumps all commands at once. I want to run Popen sequentially after the earlier process has terminated. Here is my script:

import glob, os, subprocess
import sys, re, math

exec_path='/Users/me/path/to/exec'
for name in glob.glob("*.in"):
    print name
    output = name+'.out'
    args = [exec_path, '-o', output, name]
    subprocess.Popen(args)

Thanks for your time.

Answer 1

Sounds like you need to wait for your process to end before moving on with the loop.

Your example could be rewritten like this;

import glob
import subprocess

exec_path='/Users/me/path/to/exec'
for name in glob.glob("*.in"):
    print name
    output = name + '.out'
    args = [exec_path, '-o', output, name]
    subprocess.Popen(args).wait()  # <- I've added .wait()