In swift you can use a cool feature of the switch statement in prepare(segue:)
to create cases based on the type of the destination view controller:
Example:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
switch segue.destination {
case let detailViewController as DetailViewController:
detailViewController.title = "DetailViewController"
}
case let otherViewController as OtherViewController:
otherViewController.title = "OtherViewController"
}
}
However, what if the segue is triggered by a split view controller, so the destination is a navigation controller, and what you really want to do is switch on the class of the navigation controller's top view controller?
I want to do something like this:
case let nav as UINavigationController,
let detailViewController = nav.topViewController as? DetailViewController:
//case code goes here
Where I have the same construct that I use in a multiple part if let
optional binding.
That doesn't work. Instead, I have to do a rather painful construct like this:
case let nav as UINavigationController
where nav.topViewController is DetailViewController:
guard let detailViewController = nav.topViewController as? DetailViewController
else {
break
}
detailViewController.title = "DetailViewController"
That works, but it seems needlessly verbose, and obscures the intent. Is there a way to use a multi-part optional binding in a case of a switch statment like this in Swift 3?
I worked out a decent solution to this problem.
It involves doing some setup before the switch statement, and then using a tuple in the switch statement. Here's what that looks like:
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
let dest = segue.destination
let navTopVC = (dest as? UINavigationController)?.topViewController
switch (dest, navTopVC) {
case (_, let top as VC1):
top.vc1Text = "Segue message for VC1"
case (_, let top as VC2):
top.vc2Text = "Segue message for VC2"
case (let dest as VC3, nil):
dest.vc3Text = "Segue message for VC3"
default:
break
}
}