Storing the returned values of calling a function in a loop in a list

Question

I have two functions:

1. SendMail(to, f_name, table ) - it sends a mail to the recipient using smtplib. Code snippet:

   def SendMail(to, f_name, table )
       # ...
   
       server = smtplib.SMTP_SSL('smtp.gmail.com', 465)
       server.ehlo()
       server.login(gmail_user, gmail_password)
       print("Type 'Y' to send the mail! ")
       text = input(">")
       if text.lower() == "y":
           #print("Sending mail")
           server.sendmail(gmail_user, to, msg.as_string())
           print("Mail sent to "+ first_name)
           server.close()
           status = 'success'
           return status
       else:
           print("Mail NOT sent to " + first_name)
           status = 'fail'
           return status
   

2. MailLoop(): I have a list of people that I'm sending a customised mail to.

   def MailLoop():
       for owner in owner_list:
           to = 'somemailaddress'
           f_name = 'somefirstname'
           table = 'sometable'
           SendMail(to, f_name, table)
   

How can I pass the value of status that is returned from the SendMail(to, f_name, table ) function after each iteration to the outer MailLoop() function?

I would like to store the status of each iteration in a list so that I can see and print the result after the MailLoop() function is finished.

Answer 1

Return a list from MailLoop:

def MailLoop():
    statuses = []
    for owner in owner_list:
        to = 'someemailaddress'
        f_name = 'somefirstname'
        table = 'sometable'
        statuses.append(SendMail(to, f_name, table))
    return statuses