I have the following scheme function:
(define get-ivars
(λ (ivars num)
(cond ((null? ivars) '())
(else
(append (list (car ivars) `(nth args ,num)) (list (get-ivars (cdr ivars) (+ num 1))))))))
That returns the following in a specific instance:
(x (nth args 1) (y (nth args 2) ()))
The problem is, I need it to return:
((x (nth args1)) (y (nth args 2)) ())
-the two closing parenthesis at the end should be after the (nth statements.
How would I go about getting this to work properly?
get-ivars caller:
(define gen-classes
(λ (classes)
(cond ((null? classes) '())
(else
(let* ((class (car classes)))
(eval
`(define ,(cadr class)
(λ (args)
(let (
,(get-ivars (cdr (cadddr class)) 1)
)
(eval
(let* ,(cdar (cddddr class))
(λ (method . args)
,(get-methods (cdadr (cddddr class)))
))))))))))))
That second (list ...)
in your else
clause is what's screwing you up. It's nesting each successive call deeper and deeper. The recursion will naturally create the list; you don't need to wrap it again.
Try:
(define get-ivars
(λ (ivars num)
(if (null? ivars) '()
(cons (list (car ivars) `(nth args ,num))
(get-ivars (cdr ivars) (+ num 1))))))
Regarding the get-ivars
caller code, the parentheses surrounding the unquoted call to get-ivars
are what's giving you the trouble you mention in the comments. With them, this code:
`(define ClassName
(lambda (args)
(let (,(get-ivars '(iVar1 iVar2 iVar3) 1))
;; your method-getting code
)))
Gives you this:
(define ClassName
(lambda (args)
(let (((iVar1 (nth args 1))
(iVar2 (nth args 2))
(iVar3 (nth args 3))))
;; method-getting code
)))
Which, as you can see, gives you an extra set of parentheses around the assignments in the let.
So you want to do this:
`(define ClassName
(lambda (args)
(let ,(get-ivars '(iVar1 iVar2 iVar3) 1)
;; your method-getting code
)))
get-ivars
is returning a list of lists, which is exactly what you want for the assignments in the let
, so you don't need to wrap or (as I had it earlier) splice it. Just use the unquote on its own, and the result is:
(define ClassName
(lambda (args)
(let ((iVar1 (nth args 1))
(iVar2 (nth args 2))
(iVar3 (nth args 3)))
;; method-getting code
)))
Which should do the trick.
Incidentally, I found it helpful to leave off the eval
when I was playing around with this; one can then visually inspect the result to make sure its syntax is okay.