Search file names from one list and replace them with another list in BATCH

Question

I have two files :

old_names.txt
  oldname1
  oldname2 

new_names.txt 
  newname1
  newname2 

I would like to search my folder for file names containing "old_names" and replace "old_name" string with corresponding "new_name".

for /f %%i in (old_names.txt) do (

 // get corresponding %%j new_name

 for /f %%a in ('dir /b /a-d *%%i*') do ren %%a %%j

)

How can I retrieve the corresponding new_name ?

Answer 1

As per my comment. Create a single file called names.txt and add the strings you want to replace and what you want to replace it with:

dummy replacement
dummy2 replacement2

then the script needs to be in the same directory, or you have to specify path to the files:

@echo off
setlocal enabledelayedexpansion
for /f "tokens=1,2" %%i in (names.txt) do (
  for /f %%a in ('dir /b /a-d ^| findstr "%%i"') do (
    set "oldname=%%a"
    set "newname=!oldname:%%i=%%j!"
    echo ren "!oldname!" "!newname!"
  )
)

or by specifying path:

@echo off
setlocal enabledelayedexpansion
for /f "tokens=1,2" %%i in (names.txt) do (
  for /f %%a in ('dir /b /a-d "D:\PATH" ^| findstr "%%i"') do (
    set "oldname=%%a"
    set "newname=!oldname:%%i=%%j!"
    echo ren "!oldname!" "!newname!"
  )
)

Once you are happy that it prints the files to replace to screen, simply remove the echo from the last line of code to actually perform the ren