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pythonordereddict

minimum value of an multi value OrderedDict

I have an OrderedDict that each key has more than one value.

 <key, value1, value2, value3>
 <  1,   50  ,  1000,   20   >
 <  3,   40  ,  2000,   2  >
 <  5,   30  ,  10000,  70   >
..

How can I get the key of the item that has the minimum value3? for this example, the minimum value3 would be 2. So, I want to have:

      <  3,   40  ,  2000,   2  >

or the key which is 3

Solution

  • If the values of the ordered dictionary are a tuple or list, you can use:

    d = {1: (50, 1000, 20), 3: (40, 2000, 2), 5: (30, 10000, 70)}
min(d.items(), key=lambda x: x[-1][-1])