Is it possible to avoid the warning of undefined offset PHP array?

Question

I know the undefined offset gives out warning instead of error but I want to know is there any possible way to avoid this kind of warning to pop out? I intend to write a function to test the undefined offset because I think that writing multiple similar if-else condition to test offset could be much work to be done.

function testOffset($item){
        if(isset($item)){
            return $item;
        }else{
            return "Nothing here!";
        }
    }
$array1[] = "Hello!";
echo testOffset($array1[1]);

In this case the function is work well but the warning will also pop out the moment I assign the unset element into function. Anyway to work around with it?

---

I purposely set the checking index to 1 to prove the function is working well

Answer 1

There are multiple ways of handling this problem, but depending on what you are trying to do you could do:

foreach($array as $key => $val) {}

If you are just trying to get 1 element based on the key, you should just go with array_key_exists:

$array1[] = "Hello!";
echo (array_key_exists(1, $array1)) ? $array[1] : "No key";