I receive a date from a file in this format: "EEE MMM dd hh:mm:ss z yyyy" and I'm trying to convert this value into Date "yyyy-MM-dd". For that I'm using:
TalendDate.parseDate("yyyy/MM/dd", TalendDate.formatDate("yyyy/MM/dd", TalendDate.parseDate("EEE MMM dd hh:mm:ss z yyyy",context.date)))
The context.date is defined here:
context.date = input_row.mtime_string;
But when I run my JavaRow component I get the following error:
Exception in component tJavaRow_1
"java.lang.RuntimeException: java.text.ParseException: Unparseable date: "Thu Aug 09 10:38:45 BST 2018"
How can I solve this?
Many Thanks!
You could achieve the format using the below code snippet -
System.out.println(input_row.newColumn);
SimpleDateFormat parserSDF = new SimpleDateFormat("EEE MMM dd hh:mm:ss z yyyy", Locale.ENGLISH);
Date date = parserSDF.parse(input_row.newColumn);
String dDate = null;
parserSDF = new SimpleDateFormat("yyyy-MM-dd");
dDate = parserSDF.format(date);
System.out.println(dDate);
Also, you need the below libraries to be imported(Advanced settings section of tJavaRow)-
import java.text.SimpleDateFormat;
import java.util.Locale;
import java.util.Date;
I had directly passed the input value from file(in my scenario tFileInputDelimited
) into tJavaRow
as - input_row.newColumn
and then used SimpleDateFormat
class to both parse and format dates according to the formatting pattern.
Read more here.