I have a collection with document like
{
"_id": ObjectId("5b4dd622d2ccda10c00000f0"),
"Code": "Route-001",
"Name": "Karan Nagar - Jawahar Nagar",
"StopsDetails": [
{
"StopId": "cb038446-bbad-5460-79f7-4b138024968b",
"Code": "Stop- 001",
"Name": "Lane market",
"Fee": "600"
},
{
"StopId": "2502ce2a-900e-e686-79ea-33a2305abf91",
"Code": "Stop-002",
"Name": "City center",
"Fee": "644"
}
],
"StopsTiming" :
[
....
]
}
I want to fetch all embedded documents "StopDetails" only. I am trying to tweak below lines of codes but I am not able get what to write in $query "StopsDetails" in order to fetch only StopsDetails embedded document. Please help !!!
$query = ['_id' => new MongoDB\BSON\ObjectID($this->id),
'StopsDetails' => ];
try
{
$cursor = $this->collection->find($query);
}
catch (Exception $e)
{
}
return $cursor->toArray();
You need to use projection
in the second parameter of the query
$query = ['_id' => new MongoDB\BSON\ObjectID($this->id)]
$projection = ['StopsDetails' => true]
$cursor = $this->collection->find($query, $projection);
which is similar to the javascript query
db.collection.find({ '_id': ObjectId }, { 'StopDetails': 1 })