It is unclear to me how Tornado expects to parse body arguments for all content types. It makes sense for JSON, and maybe form data, but for other body content types it is unclear to me how to format the request with CURL to get it to work.
Question: How can one use CURL to send a shell script as the POST body to Tornado? What is the formatting for the body arguments?
What I've tried:
curl -X POST -H "Content-Type: application/x-sh" http://localhost:8888/ -d script='#!/bin/bash \necho "scale=500\; 4*a(1)" | bc -l'
What I would hope or expect this to do is for Tornado to process the HTTP body so that (1) the body argument is script, and (2) the value corresponding to it is the shell script to compute pi:
#!/bin/bash
echo "scale=500\; 4*a(1)" | bc -l
Instead I just get a 400: Bad Request error, and my debugging logs show that the value of self.request.body_arguments is an empty dictionary {}.
You're sending POST data with this header - Content-Type: application/x-sh. But Tornado only supports application/x-www-form-urlencoded to parse submitted form/POST data.
Just submit the data with Content-Type: application/x-www-form-urlencoded and Tornado will make the submitted data available in body_arguments.