I am working on a hana table and i am trying to delete a table if it contains value from a list.
A B
22 01
22 01
22 02
22 06
23 01
23 01
23 06
I will like to drop some values from this table and have this.
A B
22 01
22 01
22 06
23 01
23 01
23 06
Basically i will like to most likely do a count and check if column B consists of 01 AND 02, if it does drop 02 and if it consists of only 01 leave as it is.
This seems virtually impossible with almost every sql script i have tried
SELECT BP, COUNT(*) AS SO FROM "EH"."BP_CUST" GROUP BY BP;
This scripts gets the count of each row and put it in SO column.
after that maybe do an if statement on the SO column and delete if the B field contains 01 and 02?
I tried doing and IF statement then select and i could not get it to work either.
A B
22 01
22 01
22 02
22 06
23 01
23 01
23 06
24 02
Becomes
A B
22 01
22 01
22 06
23 01
23 01
23 06
24 02
If I understand correctly, you want:
select c.*
from "EH"."BP_CUST" c
where c.b <> '02' or
not exists (select 1
from "EH"."BP_CUST" c2
where c2.a = c.a and c2.b = '01'
);
Your question says "delete". But I think the intention is to select "02" rows only when there is no "01" row for the same a
(and all other rows).