I have a big list of character vectors which looks something like this:
List of 53095
$ 30875 : chr [1:10] "<h2 class=\"buildings-page-title buildings- ...
$ 30876 : chr [1:10] "<h2 class=\"buildings-page-title buildings- ...
I want to create a data.table (or a data frame) with a single column. So what I did was:
# require(purr); require(data.table)
clean.data<-function(input){
output1<-map(input, melt)
output2<-data.frame()
for (i in 1:length(output1)) {
output2<-rbind(output2, output1[[i]])
}
return(output2)}
Using a test data as an example, what I want is
test<-list(c("hello", "world", "!"), c("Nice","to","meet","you"))
print(clean.data(test))
> print(clean.data(test))
value
1 hello
2 world
3 !
4 Nice
5 to
6 meet
7 you
But this function is incredibly slow, perhaps because my dataset is large, but I think my code is bad. Would there be any other more efficient way to get the same results?
A faster way would be to unlist
it and create a single column data.frame
data.frame(value = unlist(test))