In the following code I create a shared_ptr
in the scope and assign it to a weak_ptr
. How come when running the code I don't get SEGFAULT, because wp
should be invalid out of scope, right?
namespace {
struct Dummy {
int x;
void foo() {
std::cout << "dummy created\n";
}
~Dummy()
{
std::cout << "dummy destroyed\n";
}
};
}
TEST(experimental, ptr_test){
std::weak_ptr<Dummy> wp;
{
auto sp = std::make_shared<Dummy>();
wp = sp;
}
wp.lock()->foo();
};
You're not actually dereferencing anything there though. The lock method will still return a shared_ptr if the locked shared_ptr is null, but that shared_ptr will also be null. In this example, foo doesn't crash on my compiler since it never dereferences the null pointer but it's undefined behavior so you never know what will happen. However, bar will always crash since it needs to dereference the pointer in order to get to x.
The reason why this happens to work is that all member functions compile to normal functions that take a pointer to the object as their first parameter accessible from the function body as this. Calling this function on nullptr will probably work most of the time if nothing in the body of the function dereferences this. You shouldn't do it though, future compiler changes or a port to another architecture could cause this to crash.
#include <iostream>
#include <memory>
struct Dummy {
int x;
Dummy()
: x(10) {
std::cout << "Dummy created" << std::endl;
}
~Dummy() {
std::cout << "Dummy destroyed" << std::endl;
}
void foo() {
std::cout << "foo" << std::endl;
}
void bar() {
std::cout << x << std::endl;
}
};
int main() {
std::weak_ptr<Dummy> wp;
{
auto sp = std::make_shared<Dummy>();
wp = sp;
}
auto locked = wp.lock();
if(locked.get() == nullptr) {
std::cout << "Locked pointer is null" << std::endl;
}
locked->foo(); // Does not crash
((Dummy*)nullptr)->foo(); // Does not crash
locked->bar(); // Will crash
}