Draw 2 cards from the deck and check if they are a pair (having the same rank). Repeat this at least 1000 times and calculate the probability of drawing a pair from a deck of cards.
#include <iostream>
#include <cstdlib>
#include <cstdio>
#include <string>
using namespace std;
int counter;
string facevalue[] = { "Two", "Three", "Four", "Five", "Six", "Seven", "Eight","Nine", "Ten", "Jack", "Queen", "King", "Ace" };
string suit [] = { "Diamonds", "Hearts", "Spades", "Clubs" };
string getcard() {
string card;
int cardvalue = rand() % 13;
int cardsuit = rand() % 4;
card += facevalue[cardvalue];
card += " of ";
card += suit[cardsuit];
if(cardvalue = cardvalue){
counter = counter + 1;
}
return card;
}
int main() {
int numberofcards = 2;
int times = 1000;
for (int y =0; y < times; y++){
cout<<" "<<endl;
for (int i = 0; i < numberofcards; i++) {
cout << "You drew a " << getcard() << endl;
}
}
cout<<"counter: "<<counter<<endl;
}
So here, cardvalue controls what gets printed out from the array. So if cardvalue is 1 then facevalue[cardvalue] will be facevalue[1], which will print out "Two."
So right now I am trying to determine how many times will cardvalue be the same when picking 2 cards randomly from the deck.
I did
if(cardvalue = cardvalue){
counter = counter + 1;
}
The result I get is 926, meaning there are 926 times that the card value will be the same when drawing 2 cards out of a deck 1000 times. That doesn't seem right, would be much appreciated if anyone can correct my program or guide me through the process.
I tried (cardvalue == cardvalue)
but I get counter : 2000 instead.
If you work directly with index instead of string, you may have something like:
int color_of_card(int i)
{
return i / 13;
}
int value_of_card(int i)
{
return i % 13;
}
std::string card_as_string(int i)
{
static const std::string facevalues[] = {
"Two", "Three", "Four", "Five", "Six", "Seven",
"Eight", "Nine", "Ten", "Jack", "Queen", "King", "Ace"
};
static const std::string suits[] = { "Diamonds", "Hearts", "Spades", "Clubs" };
return facevalues[value_of_card(i)] + " of " + suits[color_of_card(i)];
}
int getcard() {
return rand() % 52;
}
int main() {
const int times = 1000;
int counter = 0;
for (int y = 0; y != times; y++)
{
auto card1 = getcard();
auto card2 = getcard();
while (card1 == card2) { card2 = getcard(); } // Ensure cards differ.
if (value_of_card(card1) == value_of_card(card2)) {
++counter;
}
}
std::cout << counter << std::endl; // 58 or 59 normally
// Once you took a card, there are only 3 card on same value
// and there is 51 remaining cards.
std::cout << 3 / 51.f << std::endl; // 0.0588235
}