How to properly schedule while function to be interrupted and another function called

Question

I have a script that runs pretty much 24/7. I would like it to be properly interrupted several times a day.

from time import sleep

def function_one():
    while True:
        print("I'm working 24/7 and doing some important stuff here!")
        print("Very important!")
        sleep(5)

def function_two():
    print("I just need to do my job once, however, function_one should be stopped while i'm working!")    

I want function_one to be interrupted (in between loops) every 3 hours then function_two to be called once and right after that function_one should continue working.

What is the proper way of doing this?

Answer 1

Why not put the call to function 2 within function 1 itself. That way it'll wait until function 2 has run to resume function 1. Something like this:

from __future__ import generators
from time import sleep
import time

def function_one():
    while True:
        print("I'm working 24/7 and doing some important stuff here!")
        print("Very important!")
        #First bit checks whether the hour is divisible by 3 (every 3 hours)
                                                #This bit checks that the minute and seconds combined are the first 5 seconds of the hour
        if int(time.strftime("%H"))%3 == 0 and int(time.strftime("%M%S")) < 6:
            #Calls function 2 and won't resume until function 2 is finished
            function_two()
            print("That was the 2 second wait from function 2")
        sleep(5)

def function_two():
    print("I just need to do my job once, however, function_one should be stopped while i'm working!")
    sleep(2)

function_one()

Hopefully this works for what you want.