I've created this application-local.json
into src/main/resources
:
{
"spring": {
"datasource": {
"url": "jdbc:postgresql://xxx:yyy/db",
"username": "xxx",
"password": "xxx",
"driverClassName": "org.postgresql.Driver"
},
"profiles": {
"active": "local"
}
}
}
By other hand, apliication.yml
:
spring:
jpa:
generate-ddl: false
show-sql: true
properties:
hibernate:
format_sql: true
jdbc:
lob:
non_contextual_creation: true
profiles:
active: local
management:
security:
enabled: false
endpoints:
web:
exposure:
include: '*'
---
spring:
profiles: local
server:
port: 8092
Currently, I'm getting this message:
***************************
APPLICATION FAILED TO START
***************************
Description:
Failed to auto-configure a DataSource: 'spring.datasource.url' is not specified and no embedded datasource could be auto-configured.
Reason: Failed to determine a suitable driver class
Action:
Consider the following:
If you want an embedded database (H2, HSQL or Derby), please put it on the classpath.
If you have database settings to be loaded from a particular profile you may need to activate it (no profiles are currently active).
When Spring application runs, it load properties from value of application.yml->spring->profiles->active. Spring supports only yml and .properties file as a source.
So, in your case Spring will look for application-local.yml or application-local.properties to read profile specific property.
But here, you have defined property file as a application-local.json and that a reason why spring is not reading values and you are getting exception.
Solution Create application-local.yml or application-local.properties and paste your content and try. It should work.
Here is sample DB configuration.
spring.datasource.url=jdbc:mysql://localhost:3306/_schema name_
spring.datasource.username=_username_
spring.datasource.password=_password_
spring.datasource.driver-class-name=com.mysql.jdbc.Driver
spring.jpa.properties.hibernate.dialect = org.hibernate.dialect.MySQL5Dialect
spring.jpa.show-sql = true
logging.level.org.hibernate.SQL=debug