I have a list of numbers and Nones like this:
l = [2., None, 3., 1., None, 2., None, 5.]
I want to get the minimum number and its index, while the Nones should simply be ignored. For the given example, the result would thus be:
(1., 3)
Of course, it is straightforward to write a function that does what I want but I would prefer some efficient built-in or at least high-level approach.
I am particularly interested in solutions for Python 3, where the min-function does not accept None as an argument.
min((v,i) for i,v in enumerate(l) if v is not None)
(1.0, 3) # (value, index)