I have a file having a structure like below:
file1.txt
:
1 10 20 A
1 10 20 B
1 10 20 E
1 10 20 F
1 12 22 C
1 13 23 X
2 33 45 D
2 48 49 D
2 48 49 E
I am trying to find out, which letters have the same information in the 1st,2nd,3rd columns? For example the output should be:
A
B
E
F
D
E
I am only able to count how many lines are unique via:
cut -f1,2,3 file1.txt | sort | uniq | wc -l
5
which does not give me anything related with the 4th column.
How do I have the letters in the forth column sharing the first three columns?
Following awk
may help you here.
awk 'FNR==NR{a[$1,$2,$3]++;next} a[$1,$2,$3]>1' Input_file Input_file
Output will be as follows.
1 10 20 A
1 10 20 B
1 10 20 E
1 10 20 F
2 48 49 D
2 48 49 E
To get only the last field's value change a[$1,$2,$3]>1
to a[$1,$2,$3]>1{print $NF}'