How to make a function play different sounds in Swift

Question

I have 10 different buttons and each button has a unique tag associated with it. All buttons are linked to the same IBAction. I have the function to play different different sounds according to the tag associated with the particular button that is clicked.

import AVFoundation

var myAudio: AVAudioPlayer!

let path = Bundle.main.path(forResource: "sound1", ofType: "wav")!
let url = URL(fileURLWithPath: path)
do {
    let sound = try AVAudioPlayer(contentsOf: url)
    myAudio = sound
    sound.play()
    } catch {
        //
    }
}

Answer 1

do like

@objc func yourbtnActionName(_ sender : UIButton){

    switch sender.tag {
    case 1:
        commonSoundCode(name: "sound1")
        break
    case 2:
        commonSoundCode(name: "yoursecondSoundname")
        break
    default:
        break
    }
   }

then common method as

 func commonSoundCode(name: String){
    let path = Bundle.main.path(forResource: name, ofType: "wav")!
    let url = URL(fileURLWithPath: path)
    do {
        let sound = try AVAudioPlayer(contentsOf: url)
        myAudio = sound
        sound.play()
    } catch {
        //
    }
}

option 2

if your sound files are in the same sequence, for e.g (sound1.wav, sound2.wav......, sound10.wav) then call like

@objc func yourbtnActionName(_ sender : UIButton){
  let path = Bundle.main.path(forResource: "sound\(sender.tag)", ofType: "wav")!
    let url = URL(fileURLWithPath: path)
    do {
        let sound = try AVAudioPlayer(contentsOf: url)
        myAudio = sound
        sound.play()
    } catch {
        //
    }

}