How would I get this string '201806070908' into a datetime object? Right now this is YYYYMMDDMMSS. I could get rid of Seconds (S) if needed. I was looking at strptime() but I'm not sure this could be used. It is possible to convert this? The time is part of a directory name and I am looking to upload the most recent file back to another machine.
If anyone can assist or point me in the right direction, then that would be great. Thanks
strptime should work:
import datetime
s = '201806070908'
dt = datetime.datetime.strptime(s, '%Y%m%d%M%S')
datetime.datetime(2018, 6, 7, 0, 9, 8)
You can test that this worked:
>>> dt.day
7
>>> dt.month
6
>>> dt.year
2018
>>> dt.minute
9
>>> dt.second
8