Django and absolute url with slug

Question

my model is like:

class Modeloxy(models.Model):
      ...
      ...
      slug = models.slug()


class mymodel(models.Model):
      marca = ...
      ...
      modelo = models.ForeignKey(Modeloxy)


      def get_absolute_url(self):
          return '/%s/%s/%s' % (self.marca,self.modelo__slug,self.pk)

So, i can't get the absolute url usin self.modelo__slug.... how i will do that?

thanks guys

Answer 1

It would be self.modelo.slug

The double underscore syntax was created to solve the problem of not being able to use dot syntax as a keyword argument function(keyword_arg=Foo) and unrelated to python: you're literally looking for a variable named modelo__slug in your case.