How to use openfiledialog to open any file as text in C#?

Question

I am writing a winforms program in C# that uses the openfiledialog. I would like it to be able to take the file that the user selected and open it as text, regardless of the file type.

I tried it like this:

if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
    textBox1.Text = Process.Start("notepad.exe", openFileDialog1.ToString()).ToString();
}

However, that didn't work and I'm not sure if I"m even on the right track.

Answer 1

You should use this code:
First add this namespace :

    using System.IO;

Then add this codes to your function:

    OpenFileDialog openFileDialog = new OpenFileDialog();
    openFileDialog.Filter = "txt files (*.txt)|*.txt|All files (*.*)|*.*";
    if (openFileDialog.ShowDialog()== DialogResult.OK)
    {
            textBox1.Text = File.ReadAllText(openFileDialog.FileName);
    }