Oracle SQL Finding the 5 lowest salaries

Question

I am trying to answer the following question. Show ID_Number and name for the five lowest paid employees.

This is the table with employees:

CREATE TABLE Employees
    (ID_No          CHAR(4)     NOT NULL,
     Name           VARCHAR(50) NOT NULL,
     Hire_Date      DATE        NOT NULL,
     Position       VARCHAR(20) CHECK(Position IN('CHAIRMAN','MANAGER','ANALYST','DESIGNER','PROGRAMMER','SALES REP','ADMIN','ACCOUNTANT')),
     Salary         NUMERIC(8,2)    NOT NULL,
     Mgr_ID_No      CHAR(4)     NULL,
     Dept_No        SMALLINT    NULL);

I will add that I've been trying a few methods and "limit" and "top" do not work for some reason.

Answer 1

In Oracle 12c :

-- more than 5 rows being returned, if multiple rows 
-- match the value of the 5th row
SELECT e.ID_No, e.Name
  FROM Employees e
 ORDER BY e.Salary  
 FETCH FIRST 5 ROWS WITH TIES;

-- only 5 rows being returned, even if multiple rows 
-- match the value of the 5th row
SELECT e.ID_No, e.Name
  FROM Employees e
 ORDER BY e.Salary  
 FETCH FIRST 5 ROWS ONLY; 

-- NEXT clause may be replaced with FIRST  
SELECT e.ID_No, e.Name
  FROM Employees e
 ORDER BY e.Salary 
 FETCH NEXT 5 ROWS ONLY; 

Prior to Oracle 12c :

SELECT e.ID_No, e.Name
  FROM ( SELECT ID_No, Name, row_number() over (order by salary) seq FROM Employees ) e
 WHERE e.seq <= 5
 ORDER BY e.seq; 

queries may be used for Top-N Queries