Combine both parent and chid JSON arrays based on the index value and add another found attribute to it.
Data: Comparison field: parentJSON - index childJSON - parent_index
Output: - parent - and its children - parent - and its children
parentJSON:
[{ index:1, name: 'a'}, {index:2, name: 'b'}, {index:3, name: 'c'}, {index:4, name: 'd'}]
childJSON:
[
{ index:1, name: 'aa', parent_index:1},
{index:2, name: 'ab', parent_index:1},
{index:3, name: 'ba', parent_index: 2},
{index:4, name: 'bb', parent_index: 2},
{index:5, name: 'ca', parent_index: 3},
{index:6, name: 'ad', parent_index: 1}
]
output:
[
{ index:1, name: 'a'},
{ index:1, name: 'aa', parent_index:1, found: true},
{ index:2, name: 'ab', parent_index:1, found: true},
{ index:6, name: 'ad', parent_index:1, found: true},
{ index:2, name: 'b'},
{ index:3, name: 'ba', parent_index:2, found: true},
{ index:4, name: 'bb', parent_index:2, found: true},
{ index:3, name: 'c'},
{ index:5, name: 'ca', parent_index:3, found: true},
{ index:4, name: 'd'},
]
let parentJSON =
[{ index:1, name: 'a'}, {index:2, name: 'b'}, {index:3, name: 'c'}, {index:4, name: 'd'}]
let childJSON =
[
{ index:1, name: 'aa', parent_index:1},
{index:2, name: 'ab', parent_index:1},
{index:3, name: 'ba', parent_index: 2},
{index:4, name: 'bb', parent_index: 2},
{index:5, name: 'ca', parent_index: 3},
{index:6, name: 'ad', parent_index: 1}
]
let answer = [];
parentJSON.forEach(parent => {
answer.push(parent);
childJSON.forEach(child => {
if(child.parent_index === parent.index){
child.found = true;
answer.push(child);
}
})
});
console.log(answer)
Without knowing how you are expecting to have childJSON
that is not exist in parentJSON
, the above solution made an assumption that all elements of childJSON
has a parent_index
link to parentJSON
.
Do let me know if you updated your question unless this is exactly what you want