Consider the following Python program:
code = """
def test():
1/0
"""
filename = "<test>"
c = compile(code, filename, 'exec')
exec(c)
import linecache
linecache.cache[filename] = (len(code), None, code.splitlines(keepends=True), filename)
import traceback
print("Traceback from the traceback module:")
print()
try:
test()
except:
traceback.print_exc()
print()
print("Regular traceback:")
print()
test()
I am dynamically defining a function that raises an exception and adding it to the linecache
. The output of the code is
Traceback from the traceback module:
Traceback (most recent call last):
File "test.py", line 20, in <module>
test()
File "<test>", line 3, in test
1/0
ZeroDivisionError: division by zero
Regular traceback:
Traceback (most recent call last):
File "test.py", line 28, in <module>
test()
File "<test>", line 3, in test
ZeroDivisionError: division by zero
If I then get a traceback from that function using the traceback
module, the line of code from the function is shown (the 1/0
part of the first traceback). But if I just let the code raise an exception and get the regular traceback from the interpreter, it doesn't show the code.
Why doesn't the regular interpreter traceback use the linecache? Is there a way to make the code appear in regular tracebacks?
The default sys.excepthook
uses a separate, C-level implementation of traceback printing, not the traceback
module. (Perhaps this is so it still works even if the system is too borked to use traceback.py
.) The C implementation doesn't try to use linecache
. You can see the code it uses to retrieve source lines in _Py_DisplaySourceLine
.
If you want tracebacks to use the traceback
module's implementation, you could replace sys.excepthook
with traceback.print_exception
:
import sys
import traceback
sys.excepthook = traceback.print_exception