So i have a command where it sends whatever the user said after the command to a website api and sends the file the site generates. However i'm changing over to aiohttp as it doesn't block like the standered requests functions
This is how i do it with normal requests and it works fine:
elif (data[0].lower() == ">signgirl"):
await bot.send_typing(message.channel)
tmp = message.content.replace(">signgirl", "")
m = hashlib.md5()
m.update(tmp.encode('utf-8'))
print(tmp, m.hexdigest())
r = requests.post("http://localhost/sign.php", stream=True, data={'text': tmp})
if (r.status_code() == 200):
await bot.send_file(destination=message.channel, filename=str(m.hexdigest()+".png"), fp=r.raw)
However when i try with aiohttp i have no idea how to actually get the raw file data.. So i made this function to get it. but it doesn't let me return an image and i cannot check the http status code without it causing an error.
async def post_data2(url, payload):
async with aiohttp.ClientSession() as session2:
async with session2.post(url, data=payload) as response2:
output = {}
output['data'] = await Image.open(BytesIO(response2.read()))
output['status'] = 200 #await str(response2.status()) #Why is this object not callable?
return output
How else could i do this? Is this possible? aiohttp doesn't seem as easy to understand.
Mister Day "V" Own from the discord.py discord server sent a perfect example of getting and sending the data
async with aiohttp.ClientSession() as session:
# or use a session you already have
async with session.get("http://example.com") as resp:
buffer = io.BytesIO(await resp.read())
# buffer is a file-like
await client.send_file(channel, fp=buffer, filename="whatever")